Optimal. Leaf size=661 \[ -\frac{27\ 3^{3/4} \left (1-\sqrt{3}\right ) a^{10/3} e \sqrt{e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt{\frac{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} (26 A b-5 a B) F\left (\cos ^{-1}\left (\frac{\left (1-\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}{\left (1+\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right )}{23296 b^{5/3} \sqrt{\frac{\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt{a+b x^3}}-\frac{81 \sqrt [4]{3} a^{10/3} e \sqrt{e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt{\frac{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} (26 A b-5 a B) E\left (\cos ^{-1}\left (\frac{\left (1-\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}{\left (1+\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right )}{11648 b^{5/3} \sqrt{\frac{\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt{a+b x^3}}+\frac{81 \left (1+\sqrt{3}\right ) a^3 e \sqrt{e x} \sqrt{a+b x^3} (26 A b-5 a B)}{11648 b^{5/3} \left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )}+\frac{27 a^2 (e x)^{5/2} \sqrt{a+b x^3} (26 A b-5 a B)}{5824 b e}+\frac{(e x)^{5/2} \left (a+b x^3\right )^{5/2} (26 A b-5 a B)}{260 b e}+\frac{3 a (e x)^{5/2} \left (a+b x^3\right )^{3/2} (26 A b-5 a B)}{728 b e}+\frac{B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e} \]
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Rubi [A] time = 1.67917, antiderivative size = 661, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.231 \[ -\frac{27\ 3^{3/4} \left (1-\sqrt{3}\right ) a^{10/3} e \sqrt{e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt{\frac{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} (26 A b-5 a B) F\left (\cos ^{-1}\left (\frac{\left (1-\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}{\left (1+\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right )}{23296 b^{5/3} \sqrt{\frac{\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt{a+b x^3}}-\frac{81 \sqrt [4]{3} a^{10/3} e \sqrt{e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt{\frac{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} (26 A b-5 a B) E\left (\cos ^{-1}\left (\frac{\left (1-\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}{\left (1+\sqrt{3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}\right )|\frac{1}{4} \left (2+\sqrt{3}\right )\right )}{11648 b^{5/3} \sqrt{\frac{\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt{a+b x^3}}+\frac{81 \left (1+\sqrt{3}\right ) a^3 e \sqrt{e x} \sqrt{a+b x^3} (26 A b-5 a B)}{11648 b^{5/3} \left (\sqrt [3]{a}+\left (1+\sqrt{3}\right ) \sqrt [3]{b} x\right )}+\frac{27 a^2 (e x)^{5/2} \sqrt{a+b x^3} (26 A b-5 a B)}{5824 b e}+\frac{(e x)^{5/2} \left (a+b x^3\right )^{5/2} (26 A b-5 a B)}{260 b e}+\frac{3 a (e x)^{5/2} \left (a+b x^3\right )^{3/2} (26 A b-5 a B)}{728 b e}+\frac{B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e} \]
Antiderivative was successfully verified.
[In] Int[(e*x)^(3/2)*(a + b*x^3)^(5/2)*(A + B*x^3),x]
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Rubi in Sympy [A] time = 91.7133, size = 605, normalized size = 0.92 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((e*x)**(3/2)*(b*x**3+a)**(5/2)*(B*x**3+A),x)
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Mathematica [C] time = 2.33076, size = 337, normalized size = 0.51 \[ \frac{e^2 \left (2 (-a)^{2/3} b x^3 \left (a+b x^3\right ) \left (a^2 (405 a B+9542 A b)+112 b^2 x^6 (55 a B+26 A b)+8 a b x^3 (625 a B+1118 A b)+2240 b^3 B x^9\right )+135 a^3 (26 A b-5 a B) \left (3 (-a)^{2/3} \left (a+b x^3\right )+(-1)^{2/3} 3^{3/4} a b^{2/3} x^2 \sqrt{\frac{(-1)^{5/6} \left (\sqrt [3]{-a}-\sqrt [3]{b} x\right )}{\sqrt [3]{b} x}} \sqrt{\frac{\frac{(-a)^{2/3}}{b^{2/3}}+\frac{\sqrt [3]{-a} x}{\sqrt [3]{b}}+x^2}{x^2}} \left ((-1)^{5/6} F\left (\sin ^{-1}\left (\frac{\sqrt{-\frac{i \sqrt [3]{-a}}{\sqrt [3]{b} x}-(-1)^{5/6}}}{\sqrt [4]{3}}\right )|\sqrt [3]{-1}\right )+\sqrt{3} E\left (\sin ^{-1}\left (\frac{\sqrt{-\frac{i \sqrt [3]{-a}}{\sqrt [3]{b} x}-(-1)^{5/6}}}{\sqrt [4]{3}}\right )|\sqrt [3]{-1}\right )\right )\right )\right )}{58240 (-a)^{2/3} b^2 \sqrt{e x} \sqrt{a+b x^3}} \]
Warning: Unable to verify antiderivative.
[In] Integrate[(e*x)^(3/2)*(a + b*x^3)^(5/2)*(A + B*x^3),x]
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Maple [C] time = 0.076, size = 6202, normalized size = 9.4 \[ \text{output too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((e*x)^(3/2)*(b*x^3+a)^(5/2)*(B*x^3+A),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int{\left (B x^{3} + A\right )}{\left (b x^{3} + a\right )}^{\frac{5}{2}} \left (e x\right )^{\frac{3}{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^3 + A)*(b*x^3 + a)^(5/2)*(e*x)^(3/2),x, algorithm="maxima")
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Fricas [F] time = 0., size = 0, normalized size = 0. \[{\rm integral}\left ({\left (B b^{2} e x^{10} +{\left (2 \, B a b + A b^{2}\right )} e x^{7} +{\left (B a^{2} + 2 \, A a b\right )} e x^{4} + A a^{2} e x\right )} \sqrt{b x^{3} + a} \sqrt{e x}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^3 + A)*(b*x^3 + a)^(5/2)*(e*x)^(3/2),x, algorithm="fricas")
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((e*x)**(3/2)*(b*x**3+a)**(5/2)*(B*x**3+A),x)
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int{\left (B x^{3} + A\right )}{\left (b x^{3} + a\right )}^{\frac{5}{2}} \left (e x\right )^{\frac{3}{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^3 + A)*(b*x^3 + a)^(5/2)*(e*x)^(3/2),x, algorithm="giac")
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